09.02.2018, 22:09
Externer Inhalt (z.B. Newsletter, E-Mails, Seiteninhalte):
Dear partners! And again we decided to please you! We announce the launch of a large-scale competition based on the results of which 9 lucky winners will receive valuable prizes from the Crypteiro platform!Webinar - https://youtu.be/uKguaVbRc80
Competition start date is 8.02.
The deadline for the contest is 24.02.
The first stage of the contest will be held on 10.02:
? 1 place - $ 300
? 2 place - 200 $
? 3 place - 100 $
The second stage of the contest will be held on 17.02:
? 1 place - Apple Watch Series 3 or cash equivalent ($ 450)
? 2nd place - $ 300
? 3rd place - $ 200
The third stage of the contest will be held on 24.02:
? 1st place - Iphone X 64GB or money equivalent ($ 1400)
? 2 place - 500 $
? 3rd place - $ 300
All winners will be selected using a randomizer. The prizes will be sent to the winners on a savings account and you will decide whether to withdraw them or open a new deposit in the platform.
Rules of participation:
1. Only those investors of the "Crypteiro" project who have an active deposit of $ 100 or the equivalent of this sum in the crypto currency can participate in the draw.
2. To participate in the drawing of prizes, you must be subscribed to the official Vkontakte project group.
3. It is necessary to repost this entry on your current Vkontakte page. Repost must be fixed and remain so until the end of the competition.
4. In the message to the rep, you must specify your ID in Telegram.
5. It is forbidden to have multi-accounts or front pages Vkontakte.
6. If one of the points is not followed, your candidature will be withdrawn from the competition.
7. Winners will be determined on the air using the special application "Randomizer".
If you have any questions, you can always contact us by one of the following contacts:
Official project page: https://crypteiro.com
Vkontakte: https://vk.com/crypteiro
Facebook: https://www.facebook.com/crypteiro
Twitter: https://twitter.com/crypteiro
Chat in Telegram: https://t.me/joinchat/Hj15RFKByWwFJ_pycltNFw
Technical support: https://t.me/Crypteiro_Support